SBI Clerk Quantitative Aptitude Test – 1
This test series contains Quant tests for SBI Clerk 2021 Pre examination. These tests will help you track how your preparation has been progressing.
1. Two candles of same height are lighted at the same time. The first is consumed in 6 hours
and second in 4 hours. Assuming that each candles burns at a constant rate, in how many
hours after being lighted, the ratio between the first and second candles becomes 2:1?
a) 1 hour
b) 2 hour
c) 3 hour
d) 4 hour
e) None of these
2. A company reduces his employee in the ratio 14 : 12 and increases their wages in the ratio
16:18, Determine whether the bill of wages increases or not and in what ratio.
a) Decreases, 28: 27
b) Increases, 27:28
c) Decreases, 29:28
d) Increases, 28:29
e) None of these
3. The average age of Yogita, Kanika and Prachi is 14 years. The ratio of Yogita‘s age
one year ago to Kanika‘s age one years hence to Prachi‘s age three years hence is 5 :
6 : 4. Find ratio of Yogita‘s age two years hence to Prachi‘s age.
A) 8 : 5
B) 5 : 3
C) 1 : 4
D) 2 : 1
E) 4 : 7
4. A man borrows 3000 rupees at 10% compound interest. At the end every year he
pays rupees 1000 back. How much amount should he pay at the end of the fourth Year to
clear all his debt?
A.Rs. 680.5
B.Rs. 651.3
C.Rs. 751.3
D.Rs. 790.3
E.None of these
5. Venkat and Vidhya have to clear their respective loans by paying 2 equal annual
instalments of Rs.30000 each. Venkat pays at 10% pa of SI and Vidhyapays at 10% CI pa.
What is the difference in their payments ?
A.200
B.300
C.400
D.500
E.None of these
Answer
1.
Answer & Explanation
Answer – c) 3 hour
Explanation :
Let height of both candles is ‘h’ and let after t times ratio between the height be 2:1
h – t*h/6 : h – t*h/4 = 2:1
2.
Answer & Explanation
Answer – a) Decreases, 28: 27
Explanation :
Let initial employee be 14a and final employee be 12a similarly initial wage is 16b and final
wage be 18b
Total initial wage = 14a * 16b = 224ab, total final wage = 12a* 18b = 216ab
So clearly wages decreases and ratio = 224ab: 216ab = 28:27
3.
Option D
Solution:
Y + K + P = 42
(Y – 1) : (K + 1) : (P + 3) = 5 : 6 : 4
So (5x + 1) + (6x – 1) + (4x – 3) = 42
Solve, x = 3
So Yogita‘s age 1 ago hence = 5x = 15, so present age = 16
Prachi‘s age 3 years hence = 4x = 12, so present age = 9
So (Y+2)/P = 18/9 = 2/1
4.
Answer & Explanation
Answer – C.Rs. 751.3
Explanation :
After one year amount = 3000 *110/100 = 3300
He pays 1000 back, so remaining = 3300-1000 =
2300
After two year amount = 2300 *110/100 = 2530
He pays 1000 back, so remaining = 2530-1000 =
1530
After three year amount = 1530*110/100 = 1683
He pays 1000 back, so remaining = 1683-1000=
683
After fouth year = 683 * 110/100 = 751.3
5.
Answer & Explanation
Answer – B.300
Explanation :
D =[(30,000 *110/100*110/100) – 30,000] –
30,000 *10*2/100
=[36300-30000]- 6000
=6300 – 6000
D = 300