SSC CGL 2018 Daily Quiz 05 – Quantitative Aptitude
SSC CGL 2018 Quantitative aptitude Practice test. Daily Quiz for SSC CGL 2018 online practice set. Daily tests with questions and answers for SSC CGL exam. Topic tests for SSC online Tier-1
1. A, B and C have 40, x and y balls with them respectively. If B gives 20 balls to A, he is left
with half as many balls as C. If together they had 60 more balls, each of them would have had
100 balls on an average. What is the ratio of x to y?
A) 4 : 3
B) 3 : 2
C) 2 : 3
D) 2 : 5
E) None
2. The incomes of A, B, C are in the ratio of 12 : 9 : 7 and their spending are in the ratio 15 : 9 :
8. If A saves 25% of his income. What is the ratio of the savings of A, B and C respectively?
A) 12:15:19
B) 11:15:18
C) 15: 18:11
D) 21:24:29
E) None
3. A Student obtained equal marks in Maths and Science. The ratio of marks in Science and
Social is 2:3 and the ratio of marks in Maths and English is 1 : 2. If he has scored an aggregate of
55% marks. The maximum marks in each subject is same. In how many subjects did he score
greater than 50% marks?
A) 1
B) 2
C) 3
D) 4
E) None
4. In a class, the number of girls is 30% more than that of the boys. The strength of the class is
92. If 8 more girls are admitted to the class, the ratio of the number of boys to that of the girls is
A) 4:5
B) 3:2
C) 2:3
D) 4:7
E) None
5. Rs 3440 is divided, among A, B, C and D such that B’s share is 6/11th of A’s; C’s share is
1/4th of B’s and D has 2/5th as much as B and C together. Find A’s share
A) 1760
B) 1540
C) 1320
D) 1850
E) None
6. When 20 is added to the numerator and denominator, then the new ratio of numerator to
denominator becomes 7:8. What is the original ratio?
A) 3:4
B) 4:5
C) 4:3
D) Can’t be determined
E) None
7. The value of the diamond is in proportion to the square of its weight A diamond was broken
into 3 parts in the ratio of 3: 4: 5, thus a loss of Rs.9.4 lakh is incurred. What is the actual value
of diamond (in lakhs)?
A) 12
B) 13.5
C) 11
D) 14.4
E) None
8. The ratio of the monthly salaries of P and Q is in the ratio 10 : 13 and that of Q and R is in the
ratio 13 : 14. Find the monthly income (in Rupees) of R if the total of their monthly salary is Rs
1,85,000.
A) 70,000
B) 81,000
C) 55,000
D) 60,000
E) None
9. Two candles of the same height are lighted at the same time. The first is consumed in 8 hrs
and second in 4 hrs. Assuming that each candle burns at a constant rate. In how many hour after
being lighted, the rate between the first and second candles become 3 : 1?
A) 2hrs 45min
B) 3hrs 12min
C) 3hrs 20min
D) 2hrs 25min
E) None
10. A boat goes 24 km upstream and 54 km downstream in 6 hrs. In 8 hrs, it can go 36 km upstream
and 48 km downstream. The speed (in km/hr) of the boat in still water is:
A) 21
B) 19.5
C) 13.75
D) 18
E) None
Answer
1. Option C
Solution:
Given,
40+x+y+60/3=100
X+y=200—1
x-20=y/2
2x-y=40—2
Solving 1 and 2
We get x=80, y=120.
Ratio of x:y=2:3
2. Option C
Solution:
Let the income be 12x, 9x, 7x and expenditure is 15y, 9y, 8y.
I-E=S
A 12x-15y=25%of 12x=3x
9x=15y==>y=3x/5
B Saving = 9x-9y
C Saving = 7x-8y
Substitute y value
Savings Ratio A:B:C
3x: 9x-9*3x/5 : 7x-8*3x/5
3x:18x/5:11x/5==>15:18:11
3. Option B
Solution:
M:S=1:1, S:So= 2:3, M:E=1:2
Then M: S: So: E=2:2:3:4
Now 2x+2x+3x+4x/4=11x/4=55%
X=20.
So Marks, M=40, S=40, So=60, E=80.
Above 50 mark is in 2 subjects
4. Option C
Solution:
G:B=130:100=13:10 Then (10+13)23 92
G 13 52
B 10 40
If 8 girls admitted then total girls is 52+8=60
Now ratio of B:G=40:60=2:3.
5. Option A
Solution:
Let A’s share be 1
Then B’s share is 6/11*1=6/11
C’s share is 6/11*1/4=3/22
D’s share is 2/5*(6/11+3/22)=3/11
A:B:C:D=1:6/11:3/22:3/11=22:12:3:6
Total 43(22+12+6+3) 3440
A’s share 22 ?==>1760
6. View Answer
Option D
Solution:
Let the fraction be x/y.
Then (x+20)/(y+20) =7/8
We have two variable and only one equation so we can’t find the solution
7. Option D
Solution:
Ratio of broken parts is 3x : 4x: 5x
Value of broken parts of diamond is (3x)2 + (4x) 2+ (5x) 2 = 50×2
The value of original diamond (3x+4x+5x)2 = 144×2
Then loss in value =144×2– 50×2=9.4 lakh
x2=10000.
The actual value of the diamond is 144 x2=14.4lakh
8. View Answer
Option A
Solution:
P/Q = 10/13 and Q/R = 13/14
So P : Q : R = 10: 13: 14
Total (10+13+14) is 37 == 1,85,000
So R’s salary 14 ? ==>70,000
9. Option B
Solution:
After x times ratio become 3:1.
Then (1-x/8)/(1-x/4)=3/1 8-x/2(4-x)=3/1
X=16/5hrs ie 3hrs 12min
10. Option B
Solution:
General method
24/u-v+54/u+v=6—1
36/u-v+48/u+v=8—2
By solving 1 and 2 we got the ans.
Shortcut
U/s…………..D/s……….t
24……………..54………..6 common terms cut= 4 9 1
36……………..48………..8 9 12 2
u/s= (4*12)-(9*9)/(9*2)-(12*1) ==u/s=33/6=5.5
d/s=(4*12)-(9*9)/(4*2)-(9*1) ==d/s=33/1=33
then U=(33+5.5)/2=38.5/2=19.25
V= (33-5.5)/2=27.5/2=13.75
