SSC CGL 2018 Daily Quiz 01 – Quantitative Aptitude
SSC CGL 2018 Quantitative aptitude Practice test. Daily Quiz for SSC CGL 2018 online practice set. Daily tests with questions and answers for SSC CGL exam. Topic tests for SSC online Tier-1
1. A and B together can complete a work in 8 days, B and C in 15 days and C and A in 12
days. They all started work together. After working for 4 days, B left the work. A and C
next worked for 3 day after which A also left. Find in how many can C alone complete
the work?
A) 25 days
B) 16 days
C) 21 days
D) 13 days
E) 22 days
2. A and B alone can complete a work in 10 and 18 days respectively. Both started the
work. After 3 days, A left and C joined B. If they completed the remaining work in 6
days, find the number of days in which C can alone complete the whole work?
A) 30 days
B) 16 days
C) 24 days
D) 18 days
E) 32 days
3. A is twice efficient than B who is one and a half times efficient than C. If C alone can
complete a wok in 18 days, then in how many days, A, B and C together can complete
11/18 of work in how many days?
A) 6 days
B) 3 days
C) 9 days
D) 4 days
E) 2 days
4. 20 men complete a work in 16 days and 25 women can complete the same work in 18
days. 8 men and 15 women started the work together. They worked for some number
of days. After they left the work, 48 children joined the work and complete the work in 4
days. If efficiency of 1 man is double the efficiency of 1 child, how many days they took
to complete the whole work?
A) 12 days
B) 16 days
C) 9 days
D) 20 days
E) 15 days
5. A camp was organized for 20 men. The food given to them can last for 40 days. After
25 days, 5 men left the camp. Find for how many more days, the remaining men can
eat remaining food?
A) 10 days
B) 2 days
C) 6 days
D) 5 days
E) 8 days
6. 25 kg of rice at Rs 20 per kg was mixed with some amount of rice at Rs 32 per kg. The
whole mixture was sell at 20% profit for Rs 32.4 per kg. Find the amount of second
variety of rice (priced at Rs 32 per kg).
A) 30 kg
B) 45 kg
C) 24 kg
D) 35 kg
E) 27 kg
7. There are 2 mixtures which contains mixture of cereals A and B. Mixture 1 contains A
and B in the ratio 4 : 5. Mixture 2 contains A and B in the ratio 8 : 3. Both the mixtures
are mixed to form a third mixture. Now the ratio of A : B becomes 8 : 5 in the resultant
mixture. If the resultant quantity if 364 kg of cereals, then find the amount of cereal B in the mixture.
A) 130 kg
B) 150 kg
C) 180 kg
D) 240 kg
E) 220 kg
8. A 84 litres mixture contains A and B in ratio 3 : 4. 14 litres of this mixture is taken out
and replaced by 10 litres of B. The resultant mixture will contain how much percent of
A?
A) 52.2%
B) 46.7%
C) 67.5%
D) 23.4%
E) 37.5%
9. A mixture contains 4/5th part of alcohol and rest water. How much mixture should be
taken out and replaced with water to make the ratio of alcohol to water reversible?
A) 3.45 l
B) 3.75 l
C) 4.25 l
D) 4.65 l
E) 5.35 l
10. There are 2 mixtures. Mixture P contains A, B and C in ratio 4 : 3 : 2. Mixture Q
contains A and B in the ratio 1 : 4. If 4 litres of mixture P is mixed with 2 litres of mixture
Q, then resultant mixture contains how much part of mixture C?
A) 1/27
B) 4/19
C) 2/31
D) 2/19
E) 1/23
1. Option B
Solution:
A, B and C together can complete work in = 2*8*15*20/(8*15 + 15*20 + 20*8) = 80/11
days
Worked for 4 days, so they did 4 * 11/80 = 11/20 work
Now A and C worked for 3 days, in 3 days they did = 3 * 1/12 = 1/4 work
So now remaining work = 1 – (11/20 + 1/4) = 1/5
C can complete whole work in – 11/80 – 1/8 = 1/80 – 80 days
So 1/5 work in 1/5 * 80 = 16 days
2. Option A
Solution:
A and B in one day = 1/10 + 1/18 = 7/45 work
So in 3 days they did = 3 * 7/45 = 7/15 work
Remaining work = 1 – 7/15 = 8/15
Let C can complete work in x days. So
(1/18 + 1/x) * 6 = 8/15
Solve, x = 30 days
3. Option E
Solution:
Efficiency ratio of A : B : C = 3x : 3x/2 : x = 6 : 3: 2
So ratio of no. of days of A : B : C is 1/6 : 1/3 : 1/2 = 1 : 2 : 3
Now C can complete work in 18 days, so
3 == 18
1 == 6
So A can complete work in 1 == 6 days and
B can complete work in 2 == 12 days
All together – 1/6 + 1/12 + 1/18 = 11/36 work in 1 day
So 11/18 work in 11/18 * 36/11 = 2 days
4. Option B
Solution:
20 m in 16 days, so 8 m in 20*16/8 = 40 days
25 w in 18 days, so 15 w in 25*18/15 = 30 days
They worked for some no. of days, so did (1/40 + 1/30)*x = 7x/120 work …… (1)
1 man can complete work in 20*16 = 320 days. So 1 child whose efficiency is half the
man, can complete whole work in 320*2 = 640 days.
So 48 children in 640/48 days
They worked for 4 days, so did 4 * 48/640 = 3/10 of work
So remaining 7/10 was done by 8 men and 15 women….. (2)
From (1) and (2)
7x/120 = 7/10 x = 12 days
So total no. of days = 12+4 = 16 days
5. Option D
Solution:
After 25 days, food left for 20 men for 15 days. Now there are 15 men. So
20*15 = 15*x
Solve, x = 20 days
So extra days = 20-15 = 5 days
6. Option D
Solution:
SP = 32.4, profit = 20%, so CP = 100/120 * 32.4 = Rs 27
So by method of allegation:
(25 kg)……………….(x kg)
20………………………..32
…………….27
5…………………………..7
5 == 25
1 == 5
7 == 35 kg
7. Option E
Solution:
B in mixture 1 = 5/9, in mixture 2 = 3/11 and in resultant mixture = 5/13
So
5/9……………………….3/11
…………….5/13
16/11*13……………….20/9*13
36 : 55
So amount of cereal B in 364 kg = 55/91 * 364 = 220 kg
8. Option E
Solution:
Total mixture = 84 l
So A in resultant mixture = 36 – 3/7 * 14 = 30 l
and B in resultant mixture = 48 – 4/7 * 14 + 10 = 50 l
So final ratio of A and B = 3 : 5
So % of A in final mixture = 3/8 * 100 = 37.5%
9. Option B
Solution:
Let total quantity = 5
So alcohol = 4, water = 1. so ratio = 4 : 1
Let mixture to be taken = x, and final ratio should be 1 : 4
So [4 – 4/5 * x]/ [1 – 1/5 * x + x] = ¼
Solve, x = 3.75l
10. Option A
Solution:
C in 1st = 2/9, C in 2nd = 0
Total mixture = 4+2 = 6 l
So C in final mixture = (2/9)/6 = 1/27
