SBI CLERK 2018 Quantitative Aptitude Quiz No- 3 “Problem on Ages”
On this quiz no 03 you will practice Problem on Ages Questions for bank exams like SBI Clerk Pre 2018, IBPS Clerk Pre, IBPS RRB 2018 and other 2018 banking exams with detailed Solution, all types of Average questions with tricky solution at free of cost
1. A person‘s present age is two-ninth of the age of his mother. After 10 years, he will be
four-eleventh of the age of his mother. How old is the mother after 15 years?
A) 48yrs
B) 60yrs
C) 55yrs
D) 53yrs
E) None
2. Ratio of the ages of A and B is 5 : x. A is 18 years younger to C. After nine years C will
be 47 years old. If the difference between the ages of A and B is same as the age of C,
what is the value of x?
A) 13
B) 12
C) 14.5
D) 13.25
E) None
3. 16 years ago, my Uncle was 8 times older than me. After 8 years from today, my uncle
will be thrice as old as I will be at that time. Eight years ago, what was the ratio of my
age and my uncle‘s age?
A) 11:53 B) 13:45
C) 8:29
D) 5:32
E) None
4. The sum of present ages of A and B is 11 times the difference of their ages. 5 years
hence, their total ages will be 13 times the difference of their ages. What is the present
age of elder one?
A) 35yrs
B) 20yrs
C) 25yrs
D) 30yrs
E) None
5. The average age of a husband-wife and their son was 42 years. The son got married
and exactly after 1 year a child was born to them. When the child became 5 years old,
the average age of the family became 36 years. What was the age of bride at the time
of marriage?
A) 30yrs
B) 27yrs
C) 25yrs
D) 22yrs
E) None
6. A says, ―If you reverse my own age, the figures represent my Brother‘s age. He is, of
course, senior to me and the difference between our ages is one-eleventh of their
sum.‖ Then A‘s brother‘s age is ?
A) 45
B) 54
C) 25
D) 52
E) None
7. L is as much younger than M as he is older than N. If the sum of the ages of M and N is
60 years, what is definitely the difference between M and L‘s age?
A) 3yrs
B) 2yrs
C) 5yrs
D) Can‘t be determined
E) None
8. If three times of the son‘s age in years is included to the mother‘s age, the total is 75
and if two times of the mother‘s age is included to the son‘s age, the total is 80. So the
son‘s age is?
A) 15yrs B) 18yrs
C) 14yrs
D) 22yrs
E) None
9. The ages of P, Q and R together are 57 years. Sis thrice as old as P and R is 12 years
older than P. Then, the difference between ages Q and R is?
A) 11yrs
B) 6yrs
C) 8yrs
D) 4yrs
E) None
10. If 10 years are subtracted from the present age of Sharmi and the remainder is divided
by 6, then the present age of his grandson Epsi is obtained. If Epsi is 2 years younger
to Nove whose age is 7 years, then what is Sharmi‘s present age?
A) 40yrs
B) 35yrs
C) 52yrs
D) 55yrs
E) None
Answer
1.Option B
Solution:
Present ratio P:M ==>2:9
After 10years P:M=4:11
Then
(2x+10)/(9x+10) = 4/11
22x+110=36x+40
X=5.
Then Mother‘s present age=9*5=45yrs.
After 15 yrs Mother‘s age is=60yrs
2.Option C
Solution:
Given
A:B=5:x –1
A = C – 18 —2
C + 9 = 47 =>C=47-9=38yrs.
A – B = C —3
From 2 A=38-18=20yrs.
From 1 20/B=5/x==> B=4x
From 3 4x-20=38
X=14.5.
3.Option A
Solution:
Let 16 yrs ago the age of mine was=x
(x+24)/(8x+24)=1/3
X=48/5=9.6
My present age is 9.6+16=25.6
Present age of my Uncle =8*9.6+16=92.8
Required ratio =(25.6-8)/(92.8-8) =17.6/84.8=11:53.
4.Option D
Solution:
A+B=11(A-B)
A:B=6:5
According to 2nd condition
6x+5x+10=13(6x-5x)=5
A‘s age =6*5=30.
5.Option C
Solution:
F+M+S=42*3=126
The age of family after 6 years =36*5=180
The age of bride after 6 years=180-(126+18+5)
=180-149==>31yrs
Age of bride at the time of marriage=31-6=25yrs
6.View Answer
Option B
Solution:
From option 54-45=1/11(45+54)
9=9
Condition satisfied
7.View Answer
Option D
Solution:
M – L = L – N
(M + N) = 2L
Given (M + N) = 60
then 2L=60==>L=30
But can‘t able to find M value
Therefore, cannot be determined.
8.View Answer
Option C
Solution:
Let daughter‘s age = A and mother‘s age = B
Given: 3A+B = 75 and A+2B = 80
Solving A, we will get A = 14
9.Option B
Solution:
Let P‘s age = X
R 12 yrs older than P so R‘s age = x+12
Q is thrice as old as P so Q‘s age = 3x
x + (x+12) + 3x = 57
=> 5x = 45
x = 9
P‘s age = 9
Q‘s age = 3x = 27
R‘s age = x+12 = 21
Q-R=27-21=6yrs
10.Option A
Solution:
Epsi age =7-2=5yrs
Let Sharmi age be x years.
Then (x-10)/6=5
X=40
