SBI CLERK 2018 Quantitative Aptitude Quiz No- 9

On this quiz no 09 you will practice Miscellaneous  Questions for bank exams like SBI Clerk Pre 2018, IBPS Clerk Pre, IBPS RRB 2018 and other 2018 banking exams with detailed Solution, all types of  questions with tricky solution at free of cost


1.A boat takes 90 minutes less to travel 36 km downstream than to travel the same
distance upstream. If the speed of the boat in still water is 10 km/h, the speed of the
stream is:
A) 3km/hr
B) 1.5km/hr
C) 2km/hr
D) 4km/hr
E) None

2. In an exam out of 1800 students, 65% boys and 80% girls are passed. If total pass
percentage was 75% , how many girls appeared in the exam and how many girls
failed?
A) 1350, 360
B) 1200, 240
C) 1000, 180
D) 1050, 280
E) None

3. The average temperature for Wednesday, Thursday and Friday was 42 Deg c. The
average for Thursday, Friday and Saturday was 43 Deg c. If temperature on Saturday
was 44 Deg c, what was the temperature on Wednesday?
A) 47 Deg c
B) 43 Deg c
C) 45 Deg c
D) 41 Deg c

4. Find the average of first 85 natural numbers.
A) 43
B) 50
C) 48
D) 53
E) None

5. On a road three consecutive traffic lights change after 40, 48 and 56 seconds
respectively. If the lights are first switched on at 10:00 AM sharp, at what time will they
change simultaneously?
A) 10.35m
B) 10.28am
C) 10.40am
D) 10.43am
E) None

6. Find the least number of five digits which when divided by 40, 60, and 75, leave
remainders 31, 51 and 66 respectively.
A) 10136
B) 10102
C) 10191
D) 10111
E) None

7. X takes 4 days to complete one-third of a job. Y takes 3 days to complete one-sixth of
the job and Z takes 5 days to complete half the job. If all of them work together for 3
days and X and Z quit, how long will it take for Y to complete the remaining work done.
A) 6
B) 5 1/10
C) 4 2/3
D) 7
E) None

8. An Employer pays Rs. 15 for each day a worker works, and forfeits Rs. 5 for each day
he is idle. At the end of 40 days, a worker gets Rs. 160. For how many days did the
worker remain idle?

A) 26
B) 28
C) 18
D) 22
E) None

9. The ratio between the length and the breadth of a rectangular park is 4 : 1. If a man
cycling along the boundary of the park at the speed of 15 km/hr completes one round in
10 minutes, then the length of the park (in sq. m) is:
A) 850
B) 1000
C) 600
D) 560
E) None

10. An error 3% in excess is made while measuring the side of a square. The percentage
of error in the calculated area of the square is:
A) 5.45%
B) 5.10%
C) 6.09%
D) 4.5%
E) None


Answer

1. Option C
Solution:
Let the speed of the stream x km/hr.
Then downstream =(10+x)
Upstream =(10-x)
36/(10-x) – 36/(10+x) =90/60
72x *60=90(100-x2 )
x2+48x-100=0
x=2km/hr.

2. View Answer
Option B
Solution:
B65 …………………G80
. 75
5 ……………………..10
Ratio 1:2.
Number of Girls 1800*2/3=1200.
Then No of girls failed=1200*20/100=240

3. Option D
Solution:
Average temperature for Wednesday, Thursday and Friday = 42 Deg c
Total temperature = 3*42 = 126 Deg c
Average temperature for Thursday, Friday and Saturday = 43 Deg c
Total temperature = 43*3 = 129 Deg c
Temperature on Saturday = 44 Deg c
Now ,
(Thursday + Friday + Saturday) – (Wednesday + Thursday + Friday) = 129-126
Saturday – Wednesday = 3
Wednesday = 44-3 = 41 Deg c.

4. Option A
Solution:
Average of 1st n natural number is given by = ([n*(n+1)]/2)/n
Average of 1st 85 natural number is given by
{([85*(86)]/2)/85} =43.

5. Option B
Solution:
LCM of 40,48,56=1680sec
Hence, the lights will change simultaneously after 28 minutes

6. Option C
Solution:
Difference, 40-31 = 9
60-51 = 9
75-66 = 9
Difference between numbers and remainder is same in each case.
Then ,
The answer = {(LCM of 40, 60, 75)-9}
LCM = 600
But, the least number of 5 digits = 10000
10000/600, we get remainder as 400.
Then, the answer = 1000-(600-400)-9; = 10191

7. Option B
Solution:
X one day work 1/12
Y one day work 1/18
Z one day work 1/10
Let Y take n days to complete remaining work then
3/12 +3/18+ 3/10+n/18=1
n/18= 1-1/4-1/6-3/10
n/18=17/60
n= (17*18)/60=5 1/10 days

8. Option D
Solution:
Suppose the worker remained idle for x days. Then,
He worked for (40 – x) days.
=15 (40 – x) – 5x =160|
600-15x-5x=160
20x=600-160
20x=440
x = 22.

9. Option B
Solution:
Perimeter = Distance covered in 10 min.
=(15000/60)*10 =2500m
Let h = 4x and b = x
Then, 2(4x + x) = 2500
x = 250.
then l=4*250 =1000.

10. Option C
Solution:
Let 100 cm is read as 103 cm.
Area 100*100=10000
Error area 103*103=10609
Diff=609.
%ge error=(609/10000)*100 =6.09%.


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